Integrand size = 21, antiderivative size = 230 \[ \int (a+a \sec (c+d x))^n \sin ^4(c+d x) \, dx=-\frac {\operatorname {AppellF1}\left (1-n,-\frac {1}{2},\frac {1}{2}-n,2-n,\cos (c+d x),-\cos (c+d x)\right ) (1+\cos (c+d x))^{\frac {1}{2}-n} (n-n \cos (c+d x)) \cot (c+d x) (a+a \sec (c+d x))^n}{d (1-n) \sqrt {1-\cos (c+d x)}}-\frac {\cos (c+d x) (a+a \sec (c+d x))^n \sin (c+d x)}{d}+\frac {2^{\frac {1}{2}+n} \operatorname {AppellF1}\left (\frac {1}{2},-4+n,\frac {1}{2}-n,\frac {3}{2},1-\cos (c+d x),\frac {1}{2} (1-\cos (c+d x))\right ) \cos ^n(c+d x) (1+\cos (c+d x))^{-\frac {1}{2}-n} (a+a \sec (c+d x))^n \sin (c+d x)}{d} \]
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Time = 0.82 (sec) , antiderivative size = 230, normalized size of antiderivative = 1.00, number of steps used = 11, number of rules used = 9, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.429, Rules used = {3961, 2960, 2866, 2865, 2864, 138, 3125, 3087, 140} \[ \int (a+a \sec (c+d x))^n \sin ^4(c+d x) \, dx=\frac {2^{n+\frac {1}{2}} \sin (c+d x) \cos ^n(c+d x) (\cos (c+d x)+1)^{-n-\frac {1}{2}} (a \sec (c+d x)+a)^n \operatorname {AppellF1}\left (\frac {1}{2},n-4,\frac {1}{2}-n,\frac {3}{2},1-\cos (c+d x),\frac {1}{2} (1-\cos (c+d x))\right )}{d}-\frac {\cot (c+d x) (n-n \cos (c+d x)) (\cos (c+d x)+1)^{\frac {1}{2}-n} (a \sec (c+d x)+a)^n \operatorname {AppellF1}\left (1-n,-\frac {1}{2},\frac {1}{2}-n,2-n,\cos (c+d x),-\cos (c+d x)\right )}{d (1-n) \sqrt {1-\cos (c+d x)}}-\frac {\sin (c+d x) \cos (c+d x) (a \sec (c+d x)+a)^n}{d} \]
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Rule 138
Rule 140
Rule 2864
Rule 2865
Rule 2866
Rule 2960
Rule 3087
Rule 3125
Rule 3961
Rubi steps \begin{align*} \text {integral}& = \left ((-\cos (c+d x))^n (-a-a \cos (c+d x))^{-n} (a+a \sec (c+d x))^n\right ) \int (-\cos (c+d x))^{-n} (-a-a \cos (c+d x))^n \sin ^4(c+d x) \, dx \\ & = \left ((-\cos (c+d x))^n (-a-a \cos (c+d x))^{-n} (a+a \sec (c+d x))^n\right ) \int (-\cos (c+d x))^{4-n} (-a-a \cos (c+d x))^n \, dx+\left ((-\cos (c+d x))^n (-a-a \cos (c+d x))^{-n} (a+a \sec (c+d x))^n\right ) \int (-\cos (c+d x))^{-n} (-a-a \cos (c+d x))^n \left (1-2 \cos ^2(c+d x)\right ) \, dx \\ & = -\frac {\cos (c+d x) (a+a \sec (c+d x))^n \sin (c+d x)}{d}+\left ((-\cos (c+d x))^n (1+\cos (c+d x))^{-n} (a+a \sec (c+d x))^n\right ) \int (-\cos (c+d x))^{4-n} (1+\cos (c+d x))^n \, dx+\frac {\left ((-\cos (c+d x))^n (-a-a \cos (c+d x))^{-n} (a+a \sec (c+d x))^n\right ) \int (-\cos (c+d x))^{-n} (-a-a \cos (c+d x))^n (2 a n-2 a n \cos (c+d x)) \, dx}{2 a} \\ & = -\frac {\cos (c+d x) (a+a \sec (c+d x))^n \sin (c+d x)}{d}+\left (\cos ^n(c+d x) (1+\cos (c+d x))^{-n} (a+a \sec (c+d x))^n\right ) \int \cos ^{4-n}(c+d x) (1+\cos (c+d x))^n \, dx-\frac {\left ((-\cos (c+d x))^n (-a-a \cos (c+d x))^{\frac {1}{2}-n} \sqrt {2 a n-2 a n \cos (c+d x)} \csc (c+d x) (a+a \sec (c+d x))^n\right ) \text {Subst}\left (\int (-x)^{-n} (-a-a x)^{-\frac {1}{2}+n} \sqrt {2 a n-2 a n x} \, dx,x,\cos (c+d x)\right )}{2 a d} \\ & = -\frac {\cos (c+d x) (a+a \sec (c+d x))^n \sin (c+d x)}{d}-\frac {\left ((-\cos (c+d x))^n (1+\cos (c+d x))^{\frac {1}{2}-n} \sqrt {2 a n-2 a n \cos (c+d x)} \csc (c+d x) (a+a \sec (c+d x))^n\right ) \text {Subst}\left (\int (-x)^{-n} (1+x)^{-\frac {1}{2}+n} \sqrt {2 a n-2 a n x} \, dx,x,\cos (c+d x)\right )}{2 a d}+\frac {\left (\cos ^n(c+d x) (1+\cos (c+d x))^{-\frac {1}{2}-n} (a+a \sec (c+d x))^n \sin (c+d x)\right ) \text {Subst}\left (\int \frac {(1-x)^{4-n} (2-x)^{-\frac {1}{2}+n}}{\sqrt {x}} \, dx,x,1-\cos (c+d x)\right )}{d \sqrt {1-\cos (c+d x)}} \\ & = -\frac {\cos (c+d x) (a+a \sec (c+d x))^n \sin (c+d x)}{d}+\frac {2^{\frac {1}{2}+n} \operatorname {AppellF1}\left (\frac {1}{2},-4+n,\frac {1}{2}-n,\frac {3}{2},1-\cos (c+d x),\frac {1}{2} (1-\cos (c+d x))\right ) \cos ^n(c+d x) (1+\cos (c+d x))^{-\frac {1}{2}-n} (a+a \sec (c+d x))^n \sin (c+d x)}{d}-\frac {\left ((-\cos (c+d x))^n (1+\cos (c+d x))^{\frac {1}{2}-n} (2 a n-2 a n \cos (c+d x)) \csc (c+d x) (a+a \sec (c+d x))^n\right ) \text {Subst}\left (\int \sqrt {1-x} (-x)^{-n} (1+x)^{-\frac {1}{2}+n} \, dx,x,\cos (c+d x)\right )}{2 a d \sqrt {1-\cos (c+d x)}} \\ & = -\frac {\operatorname {AppellF1}\left (1-n,-\frac {1}{2},\frac {1}{2}-n,2-n,\cos (c+d x),-\cos (c+d x)\right ) (1+\cos (c+d x))^{\frac {1}{2}-n} (n-n \cos (c+d x)) \cot (c+d x) (a+a \sec (c+d x))^n}{d (1-n) \sqrt {1-\cos (c+d x)}}-\frac {\cos (c+d x) (a+a \sec (c+d x))^n \sin (c+d x)}{d}+\frac {2^{\frac {1}{2}+n} \operatorname {AppellF1}\left (\frac {1}{2},-4+n,\frac {1}{2}-n,\frac {3}{2},1-\cos (c+d x),\frac {1}{2} (1-\cos (c+d x))\right ) \cos ^n(c+d x) (1+\cos (c+d x))^{-\frac {1}{2}-n} (a+a \sec (c+d x))^n \sin (c+d x)}{d} \\ \end{align*}
Result contains complex when optimal does not.
Time = 21.75 (sec) , antiderivative size = 7069, normalized size of antiderivative = 30.73 \[ \int (a+a \sec (c+d x))^n \sin ^4(c+d x) \, dx=\text {Result too large to show} \]
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\[\int \left (a +a \sec \left (d x +c \right )\right )^{n} \sin \left (d x +c \right )^{4}d x\]
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\[ \int (a+a \sec (c+d x))^n \sin ^4(c+d x) \, dx=\int { {\left (a \sec \left (d x + c\right ) + a\right )}^{n} \sin \left (d x + c\right )^{4} \,d x } \]
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Timed out. \[ \int (a+a \sec (c+d x))^n \sin ^4(c+d x) \, dx=\text {Timed out} \]
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\[ \int (a+a \sec (c+d x))^n \sin ^4(c+d x) \, dx=\int { {\left (a \sec \left (d x + c\right ) + a\right )}^{n} \sin \left (d x + c\right )^{4} \,d x } \]
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\[ \int (a+a \sec (c+d x))^n \sin ^4(c+d x) \, dx=\int { {\left (a \sec \left (d x + c\right ) + a\right )}^{n} \sin \left (d x + c\right )^{4} \,d x } \]
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Timed out. \[ \int (a+a \sec (c+d x))^n \sin ^4(c+d x) \, dx=\int {\sin \left (c+d\,x\right )}^4\,{\left (a+\frac {a}{\cos \left (c+d\,x\right )}\right )}^n \,d x \]
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